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Daniell Phillips

Answered question

2021-12-30

A hydrogen atom is in its n = 1 state. In the Bohr model, what is the ratio of its kinetic energy to its potential energy?

Answer & Explanation

recoronarrv

Beginner2021-12-31Added 20 answers

If we know that the Bohr model assumes stationary states, i.e a zero net force we can use the expression Extra close brace or missing open brace $F_{C o u l} = F_{c e n t}$ to express the kinetic energy through the potential energy.
$K \times \frac{q^{2}}{r^{2}} = \frac{m v^{2}}{r}$
If we multiply the equation by $\frac{r}{w}$ we get
$2 K \times \frac{q^{2}}{r} = \frac{m v^{2}}{2}$
Which is $- 2 E_{p} = K$ and gives that $\frac{e_{p}}{K} = - \frac{1}{2}$

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