abreviatsjw

2022-01-01

A +5.0 μC charge experiences a 0.57 N force in the positive y direction.

If this charge is replaced with a −2.7 μC charge, find the magnitude of the force in this case.

If this charge is replaced with a −2.7 μC charge, find the magnitude of the force in this case.

Laura Worden

Beginner2022-01-02Added 45 answers

Let $q}_{1$ be the initial charge, $F}_{1$ be the force on this charge, E be electric field present in the region, $q}_{2$ be the new charge, and $F}_{2$ be the force on this charge.

Write the expression to find the electric field in the region.

$\overrightarrow{E}=\frac{\overrightarrow{{F}_{1}}}{{q}_{1}}$

$=\frac{\left(0.576j\right)\text{}N}{5\mu C}$

$=(0.114\times {10}^{-6}j)\text{}\frac{N}{C}$

Write the expression for the force on the new charge.

$\overrightarrow{{F}_{2}}={q}_{2}\overrightarrow{E}$

$=(-2.7\mu C)\left((0.114\times {10}^{-6}j)\frac{N}{C}\right)$

$=-0.3078j\text{}N$

The magnitude of the force is 0.3078 N and it will be in negative y-direction.

Write the expression to find the electric field in the region.

Write the expression for the force on the new charge.

The magnitude of the force is 0.3078 N and it will be in negative y-direction.

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