Expert Answer to "A +5.0 μC charge experiences a 0.57 N..."

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abreviatsjw

Answered question

2022-01-01

A +5.0 μC charge experiences a 0.57 N force in the positive y direction.
If this charge is replaced with a −2.7 μC charge, find the magnitude of the force in this case.

Answer & Explanation

Laura Worden

Beginner2022-01-02Added 45 answers

Let

q_{1}

be the initial charge,

F_{1}

be the force on this charge, E be electric field present in the region,

q_{2}

be the new charge, and

F_{2}

be the force on this charge.
Write the expression to find the electric field in the region.

\vec{E} = \frac{\vec{F_{1}}}{q_{1}}

= \frac{(0.576 j) N}{5 μ C}

= (0.114 \times 10^{- 6} j) \frac{N}{C}

Write the expression for the force on the new charge.

\vec{F_{2}} = q_{2} \vec{E}

= (- 2.7 μ C) ((0.114 \times 10^{- 6} j) \frac{N}{C})

= - 0.3078 j N

The magnitude of the force is 0.3078 N and it will be in negative y-direction.

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