diferira7c

2022-01-07

Two large, parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. (a) If the surface charge density for each plate has magnitude

Fasaniu

Beginner2022-01-08Added 46 answers

Step 1

Given:

$\sigma}_{a}=47.0nC\cdot {m}^{2$

$\sigma}_{b}=-47.0nC\cdot {m}^{2$

d=2.2 cm

Required

a)E betwween them.

b)V between them.

c)If d becomes 2d find E and V.

Step 2

a)According to electric field for parallel plstes the electric field of infinite parallel plates is given by

$E=\frac{\sigma}{2{\in}_{0}}\Rightarrow \left(1\right)$

So the field is independent on d so the net field is

$$E={E}_{1}+{E}_{2}=\frac{\sigma}{2{\in}_{0}}+\frac{\sigma}{2{\in}_{0}}=\begin{array}{|c|}\hline \frac{\sigma}{{\in}_{0}}\\ \hline\end{array}$$

Substitution in (1) yields

$$E=\frac{47\times {10}^{-9}}{8.85\times {10}^{-12}}=\begin{array}{|c|}\hline 5.3\times {10}^{3}N/C\\ \hline\end{array}$$

Given:

d=2.2 cm

Required

a)E betwween them.

b)V between them.

c)If d becomes 2d find E and V.

Step 2

a)According to electric field for parallel plstes the electric field of infinite parallel plates is given by

So the field is independent on d so the net field is

Substitution in (1) yields

Elois Puryear

Beginner2022-01-09Added 30 answers

Step 3

b)According to example (23.9) Since the electric potential between tham at any point and is given by

$V=Ed\Rightarrow \left(2\right)$

So Sumstitution in (2) yields

$$V=2.2\times {10}^{-2}\times 5.3\times {10}^{3}=\begin{array}{|c|}\hline 116.6V\\ \hline\end{array}$$

b)According to example (23.9) Since the electric potential between tham at any point and is given by

So Sumstitution in (2) yields

karton

Expert2022-01-10Added 613 answers

Step 4

c)If the distance between plantes is doubled it wiil make no changes on the field because the field is independent on d.For the voltage, according to (2) the voltage depends on d so if d is doubled then the potential between plantes must be doubled.

Result

a)

b)

c) E is independent on d so it won`t change, but the potential depends on d so if d is doubled then V must be doubled.

22+64

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