kramtus51

2022-01-06

How many atoms are in

Kirsten Davis

Step 1
atoms
To determine the number of atoms, dimly multiply the number of moles by $6.022×{10}^{23}$ or Avogadros

aquariump9

Step 1
To find the number of atoms in any quantity of moles you just need to multiply the number of, moles times Avogadro's constant.
Which will gives the number of molecules, and then multiply by the number of atoms is one molecule which is
.
The calculus is $1.75mol×6.02×{10}^{23}$ $\frac{molecules}{mol}×5\frac{atoms}{molecule}$

$=5.2675×{10}^{24}$ atoms.

karton

(atoms or molecules)
1.75 moles of $\left(CHC{l}_{3}\right)$ we have: $1.75moles×\left(6.022×{10}^{23}molecules\right)=1.05385×{10}^{25}$ molecules.
a molecule of $CHC{l}_{3}$ have, 1 atom of C, 1 atom of H, and 3 atoms of Cl, therefore a molecule of
Therefore:

Solution: $=5.269×{10}^{24}$ atoms.

Jeffrey Jordon

To determine the number of atoms in 1.75 mol of CHCl${}_{3}$, we need to first calculate the total number of molecules in 1.75 mol of CHCl${}_{3}$, and then multiply that by the number of atoms in each molecule.
The molecular formula of CHCl${}_{3}$ indicates that it contains 1 carbon atom, 1 hydrogen atom, and 3 chlorine atoms.
Avogadro's number, ${N}_{\text{A}}$, is the number of particles in one mole of a substance, and is equal to $6.022×{10}^{23}$ particles/mol.
Therefore, the number of CHCl${}_{3}$ molecules in 1.75 mol is:

Since each CHCl${}_{3}$ molecule contains 1 carbon atom, 1 hydrogen atom, and 3 chlorine atoms, the total number of atoms in 1.057 $×$ 10${}^{24}$ molecules of CHCl${}_{3}$ is:

Therefore, there are $5.285×{10}^{24}$ atoms in 1.75 mol of CHCl${}_{3}$.

RizerMix

The molar mass of CHCl${}_{3}$ can be calculated by adding the atomic masses of its constituent atoms:
$1×\text{C}=12.01$ g/mol
$1×\text{H}=1.01$ g/mol
$3×\text{Cl}=3×35.45$ g/mol
Adding these values together gives a molar mass of:
$12.01$ g/mol $+1.01$ g/mol $+3×35.45$ g/mol $=119.38$ g/mol
This means that 1 mole of CHCl${}_{3}$ has a mass of 119.38 g.
Since we have 1.75 moles of CHCl${}_{3}$, we can find the mass of this quantity:
$1.75$ mol $×119.38$ g/mol $=208.76$ g
Now, we can use Avogadro's number to determine the number of atoms in 1.75 mol of CHCl${}_{3}$:
$1.75$ mol $×6.022×{10}^{23}$ atoms/mol $=1.057×{10}^{24}$ atoms
Therefore, there are $1.057×{10}^{24}$ atoms in 1.75 mol of CHCl${}_{3}$.

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