Lucy and her friend are working at an assembly plant making wooden toy giraffes. At the end of the line, the giraffes go horizontally off the edge of the conveyor belt and fall into a box below. If the box is 0.6 m below the level of the conveyor belt and 0.4 m away from it, what must be the horizontal velocity of giraffes as they leave the conveyor belt?

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Suhadolahbb · Accepted Answer

It takes t seconds the giraffes to reach the bottom of the belt:  t=−2yg=−2⋅(−0.6)9.8=0.35s  The velocity of the giraffes must be:  vx=xt=0.40.35=1.1ms

enlacamig · Accepted Answer

Since the giraffes are going off horizontally, there is noinitial vertical velocity y=voyt+12gt2 so t=2yg=2⋅−0.6m−9.8ms2=0.35s in the air x=v⊗t so vo=xt=0.4m0.35s=1.14ms Hope that helps

karton · Accepted Answer

x=vxt=vx−2ygso vx=x−2yg=0.4m(−2)(−0.6m)9.80m/s2=1m/s

user_27qwe · Accepted Answer

To solve the problem, we can use the principle of projectile motion. The horizontal velocity of the giraffes as they leave the conveyor belt can be determined using the following equation:vx=dtwhere vx is the horizontal velocity, d is the horizontal distance, and t is the time of flight.In this case, the horizontal distance is given as 0.4 m, and the time of flight can be determined using the equation:t=2hgwhere h is the vertical distance and g is the acceleration due to gravity.Given that the vertical distance is 0.6 m, and the acceleration due to gravity is approximately 9.8m/s2, we can substitute these values into the equation for time of flight.t=2·0.6m9.8m/s2Simplifying the equation:t=0.129.8≈0.109sNow, we can substitute the values of d and t into the equation for horizontal velocity:vx=0.4m0.109s≈3.67m/sTherefore, the horizontal velocity of the giraffes as they leave the conveyor belt is approximately 3.67m/s.

star233 · Accepted Answer

Step 1: Let&#039;s denote the horizontal velocity of the giraffes as vx and the vertical velocity as vy. We are given that the vertical displacement (Δy) is 0.6 m and the horizontal displacement (Δx) is 0.4 m.Using the equation of motion for vertical displacement, we have:Δy=vy·t+12·g·t2where t is the time of flight and g is the acceleration due to gravity (approximately 9.8 m/s2). Since the giraffes fall vertically, their initial vertical velocity is zero (as they leave the conveyor belt horizontally). Thus, the equation simplifies to:0.6=12·9.8·t2Simplifying further, we get:0.6=4.9·t2⇒t2=0.64.9⇒t≈0.273sStep 2: Now, we can use the equation of motion for horizontal displacement:Δx=vx·tSubstituting the given values, we have:0.4=vx·0.273⇒vx=0.40.273⇒vx≈1.466m/sTherefore, the horizontal velocity of the giraffes as they leave the conveyor belt is approximately 1.466 m/s.

Lucy and her friend are working at an assembly plant making wooden toy

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