Write an equation to solve each problem. Two planes left an airport at noon. One flew east and the other flew west at twice the speed. After 3 hours the planes were 2700 mi apart. How fast was each plane flying?

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Write an equation to solve each problem.   Two planes left an airport at noon. One flew east and the other flew west at twice the speed. After 3 hours the planes were 2700 mi apart. How fast was each plane flying?

Jeremy Merritt · Accepted Answer

Let x be the speed of the slower plane going east in mi/hr  2x is the speed of the plane going west.  speed⋅time=distan⁡ce  If they are 2700 mi apart in 3 hr then  x⋅3+2x⋅3=2700  3x+6x=2700  9x=2700  x=300mihr  So the faster plane flew at 60 mi/hr.  East at 300mi/hr, west at 600 mi/hr

Lynne Trussell · Accepted Answer

If we call the speed of the first plane v then the other plane has a speed of 2⋅v  Explanation:  So the distance between the planes will get greater by  v+2⋅v=3⋅v every hour  So in three hours their distance will be:  3⋅3⋅v which is equal to 2700 mi.  So 9⋅v=2700⇒v=27009=300∓h  And the other plane had twice that speed: 600mph

karton · Accepted Answer

x= speed of the first plane. (east) 2x= speed of the second plane (west). we can suggest this equation: 3(x+2x)=2700 3(3x)=2700 9x=2700 x=27009 x=300 speed of the first plane =300 miles/h speed of the second plane =2x=2(300 miles/h)=600 miles/h Answer: the speed of the first plane was 300 miles/h, and the speed of the second plane was 600 miles/h.

Write an equation to solve each problem. Two planes left an

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