Gregory Jones

2022-01-07

A heat engine that pumps water out of an underground mine accepts 700 kJ of heat and produces 250 kJ of work. How much heat does it reject, in kJ?

kaluitagf

Beginner2022-01-08Added 38 answers

The heat rejection is to be determined.

Applying the first law to the heat engine gives

$Q}_{L}={Q}_{h}-{W}_{\ne t$

we substitute the values in the equation.

${Q}_{L}=700KJ-250KJ$

Answer:

${Q}_{L}=450KJ$

Debbie Moore

Beginner2022-01-09Added 43 answers

Rejected heat

karton

Expert2022-01-11Added 613 answers

Step 1

We know:

Heat input, Q in = 700 kJ

Work, W = 250 kJ

Step 2

Utilizing the formula

$W={Q}_{in}-{Q}_{out}$

$250=700-{Q}_{out}$

${Q}_{out}=450k$

Hence, the output heat is 450 kJ.

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