Get the solution to "A heat engine that pumps water out of..."

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Gregory Jones

Answered question

2022-01-07

A heat engine that pumps water out of an underground mine accepts 700 kJ of heat and produces 250 kJ of work. How much heat does it reject, in kJ?

Answer & Explanation

kaluitagf

Beginner2022-01-08Added 38 answers

The heat rejection is to be determined.
Applying the first law to the heat engine gives
$Q_{L} = Q_{h} - W_{\neq t}$
we substitute the values in the equation.
$Q_{L} = 700 K J - 250 K J$
Answer:

$Q_{L} = 450 K J$

Debbie Moore

Beginner2022-01-09Added 43 answers

$Q_{i n} = 700 k J, W = 250 k J$
Rejected heat
$Q_{o u t} = 700 - 250 = 450 k J$

karton

Expert2022-01-11Added 613 answers

Step 1
We know:
Heat input, Q in = 700 kJ
Work, W = 250 kJ
Step 2
Utilizing the formula
$W = Q_{i n} - Q_{o u t}$
$250 = 700 - Q_{o u t}$
$Q_{o u t} = 450 k$
Hence, the output heat is 450 kJ.

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