An Australian emu is running due north in a straight line at a speed o

Holly Guerrero

Holly Guerrero

Answered question

2022-01-06

An Australian emu is running due north in a straight line at a speed of 13.0ms and slows down to a speed of 10.6ms in 40 s.
a) What is the direction of the birds

Answer & Explanation

boronganfh

boronganfh

Beginner2022-01-07Added 33 answers

(a) The emu is moving to the north with speed of υ0=13ms1 then it slows down to a speed of υ=10.6ms1 during time interval of t = 4. The difference in the speeds is negative so according to:
υυ0=at
the acceleration must be negative (the time is always positive), so its in the opposite direction of the speeds, which
is to the north. And it has a magnitude of
a=υυ0t
=(10.6ms1)(13ms1)4s
=0.6ms2
a=0.6ms2
(b) Assume that the acceleration remains constant, we can get the final velocity after additional time of 2s, so t=2+4=6s, using (1), the final velocity is therefore:
υ=υ0+at
=(13ms1)+(0.6ms2)(6s)
=9.4ms1
the final speed is therefore:
υ=9.4ms1

Karen Robbins

Karen Robbins

Beginner2022-01-08Added 49 answers

The acceleration of the bird is the quotient obtained when the difference of its final and initial velocities is divided by the time elapsed.
a=VfV1
a=10.6ms13ms4=0.6ms2
Thus, the acceleration is equal to -0.6 m/s2
. For the velocity after 2 seconds,
Vf2=Vf1+at
Substituting,
Vf2=10.6ms+(0.6)×2=9.4ms

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