A piece of aluminum foil 1.00 cm square and 0.570

Lucille Davidson

Lucille Davidson

Answered question

2022-01-10

A piece of aluminum foil 1.00 cm square and 0.570 mm thick is allowed to react with bromine to form aluminum bromide. How many moles of aluminum were used? (The density of aluminum is 2.699 g/cm3.)

Answer & Explanation

Linda Birchfield

Linda Birchfield

Beginner2022-01-11Added 39 answers

Using the given area and thickness, find the volume of aluminum foil.
Volume=1.00cm2×0.570mm×1 cm10 mm
=0.057 cm3
From the given density and obtained volume, calculate the mass of foil.
Mass=Density×Volume
=2.699 gcm3×0.057 cm3
=0.514 g
From the obtained mass and molar mass of aluminum, calculate the amount of moles used as below.
Mole=MassMolar mass
=0.154 g26.98 molg
=0.00571 moles
Answer:
The moles of aluminium used were 0.00571 moles.

Jeffery Autrey

Jeffery Autrey

Beginner2022-01-12Added 35 answers

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