aramutselv

2022-01-10

A solution contains

zesponderyd

Beginner2022-01-11Added 41 answers

Step 1

$C{r}^{3+}+3{F}^{-}\Rightarrow Cr{F}_{3}$

$M{g}^{2+}+2{F}^{-}\Rightarrow Mg{F}_{2}$

Write a balanced chemical equation

Step 2

$\frac{x\text{}mol}{1.0L}=1.51M$

Solve for moles using Molarity

Step 3

$x=1.51mol$

Multiply 1.51 by 1.0 to get 1.51 moles

Step 4

$49.6g\cdot \frac{1\text{}mol}{109.0g}\cdot \frac{3\text{}mol}{1\text{}mol}=1.36mol$

109.0 is obtained by the molar mass of CrF3$(52+3\left(19\right))$

Step 5

$49.6g\cdot \frac{1\text{}mol}{62.3g}\cdot \frac{2\text{}mol}{1\text{}mol}=1.59(1-x)$

Step 6

$(1.37x+1.59-1.59x)mol=1.51mol$

Step 7

$x=0.36$

Step 8

$0.36\cdot 49.6=18g$

Multiply 0.36 by the total mass

Step 9

$18\cdot \frac{1\text{}mol}{(52.0+3\left(19.0\right))}\cdot \frac{52.0g}{1\text{}mol}=8.6g\text{}Cr3+$

Convert 18 grams to moles then to moles of Cr3+

Write a balanced chemical equation

Step 2

Solve for moles using Molarity

Step 3

Multiply 1.51 by 1.0 to get 1.51 moles

Step 4

109.0 is obtained by the molar mass of CrF3

Step 5

Step 6

Step 7

Step 8

Multiply 0.36 by the total mass

Step 9

Convert 18 grams to moles then to moles of Cr3+

Ronnie Schechter

Beginner2022-01-12Added 27 answers

Step 1

The molarity of the sodium fluoride (NaF) solution is 1.51 M.

The volume of the solution

Now, determine the number of moles of NaF present in the solution.

Moles of

1 mol of NaF gives 1 mole of

Step 2

According to the given data, 1.55 moles of

The total mass of precipitate

The mass of

The molar mass of

Based on this data the following equation is:

Step 3

Simplify and solve equations (1) and (2) to get x and y values:

Substitute this y value in equation (1), to get

Thus

Step 4

The molar mass of chromium ion

The number of moles of

Mass of

Therefore, the mass of the

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