An ice-cube tray of negligible mass contains 2.5

Answered question

2022-04-29

An ice-cube tray of negligible mass contains 2.5 kg of water at 20°C. How much heat must be removed to cool the water to 0°C and freeze it?
 

Answer & Explanation

star233

star233

Skilled2022-05-14Added 403 answers

mwater=2.5 kg

T = 0 -20 = - 20°C

cwater=4190 J/kg°C

Lf.water=3.34*105 J/kg

Qgain+Qloss=0

Qgain+mwater*cwater*T-mwater*Lf.water=0

Qgain=-mwater*cwater*deltT+mwater*Lf.water=-2.5*4190*(-20)*2.5*3.34*105

=1.749325*1011 J

=165804018,4 Btu

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