2022-05-04

How many injective functions are there from a set with 3^10 elements to a set with 2^20 elements

user_27qwe

Skilled2022-07-02Added 375 answers

first element has no choise, so for injective 2nd has 19 choise, similary so,

total number of function = ${20}^{5}$

total number of injective function = $20(20-1)(20-2)(20-3)(20-4)$

= $20\times 19\times 18\times 17\times 16$

$\therefore $ total number of not injective function = ${20}^{5}-20\times 19\times 18\times 17\times 16$

= $1339520$

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