Describe all solutions of Ax=0 in parametric vector form, where A is row equivalent to the given matrix[130−4260−8]

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pandurorc2x · Accepted Answer

To find all solutions of the equation Ax=0, where A is row equivalent to the matrix [130−4260−8], we need to find the parametric vector form of the solutions.We can start by performing row reduction on the augmented matrix [130−4260−8].Applying row operations, we obtain the row-reduced form:[130−40000]The second row indicates that we have a free variable. Let&#039;s call it t.Now, we can express the solutions in terms of the free variable t. Rewriting the row-reduced form as equations, we have:x+3y−4z=00=0We can solve the first equation for x:x=−3y+4zExpressing the solution in vector form, we have:[xyz]=[−3y+4zyz]=y[−310]+z[401]Therefore, the solutions of the equation Ax=0 in parametric vector form are:[xyz]=y[−310]+z[401]where y and z are real numbers that serve as parameters.

Describe all solutions of Ax=0 in parametric vector form, where A is row equival

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