Ezequiel Olson

2022-04-28

Energy of photon given temperautre

I have a question asking to find the energy of a photon emitted from mater of temperature $T$. If the question had asked frequency, it would have clearly been that ${E}_{photon}=h\cdot f$. I do know that classically, the energy of an oscillator is $E={K}_{b}\cdot T$. Is it okay to use this formula for this question?

I have a question asking to find the energy of a photon emitted from mater of temperature $T$. If the question had asked frequency, it would have clearly been that ${E}_{photon}=h\cdot f$. I do know that classically, the energy of an oscillator is $E={K}_{b}\cdot T$. Is it okay to use this formula for this question?

Araceli Soto

Beginner2022-04-26Added 1 answers

According to the physics of blackbody radiation, Wien's displacement law states that the peak (i.e. most probable) wavelength of radiation from a perfect blackbody at temperature $T$ is given by

${\lambda}_{peak}=\frac{2.898\times {10}^{-3}m\cdot K}{T}$

From the wavelength you can, of course, calculate the frequency and therefore the energy.

I am making an assumption that this probably wants you to make the approximation that the object is close to a perfect blackbody, and that you've probably measured more than just "one photon" so you actually know the most common photon wavelength coming out.

${\lambda}_{peak}=\frac{2.898\times {10}^{-3}m\cdot K}{T}$

From the wavelength you can, of course, calculate the frequency and therefore the energy.

I am making an assumption that this probably wants you to make the approximation that the object is close to a perfect blackbody, and that you've probably measured more than just "one photon" so you actually know the most common photon wavelength coming out.

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