Are De Broglie relations only applicable to particles that have zero potential energy? De Broglie

Regina Ewing

Regina Ewing

Answered question

2022-05-18

Are De Broglie relations only applicable to particles that have zero potential energy?
De Broglie relations are always written as:
E = h ν
p = h λ
However, it doesn't make sense when you have waves that are eigenstates of a Hamiltonian operator with a non-zero potential. That is because that would give us a direct relation between momentum and energy: E p = v p , where v p is the phase velocity. This doesn't seem to make sense to me. So, would these equations be the same with the electron of the hydrogen atom, for example?

Answer & Explanation

Kaylin Barry

Kaylin Barry

Beginner2022-05-19Added 11 answers

De Broglie's proposition is a limited-validity rule assigning a travelling wave to a freely moving particle. If we have eigenstates of a Hamiltonian with some potential term, we refer to Schroedinger's theory instead, which describes more complicated situations than de Broglie relations do.
The relation
ν = E h
is still valid in Schroedinger's description of Hamiltonian eigenstates, here ν is frequency of oscillation of function Ψ. This reminds of de Broglie's wave, but Ψ of an Hamiltonian eigenstate is usually not a plane wave. It is usually some function concentrated in those regions of configuration space that are probable configurations of the system. For single electron atom, Ψ is concentrated near the nucleus and it is not a travelling wave.
Hence, the relation
λ = h p
is usually no longer applicable in this context, as there is no single momentum p of the electron. Energy eigenstates have definite energy, but usually do not have definite momentum.

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