Nayeli Osborne

2022-10-11

What scattering angle in the Compton Effect produces a maximum change in frequency?

elulamami

Beginner2022-10-12Added 22 answers

Calculation:

Write the expression for the change in wavelength of the Compton effect.

$\mathrm{\u25b3}\lambda =\frac{h}{{m}_{e}c}(1-\mathrm{cos}\theta )$

Here, $\mathrm{\u25b3}\lambda $ is the change in waveleght, h is Plak's constant, me is mass of the electron and $\theta $ is scattering angle.

For the maximum change in frequency, the change in wavelength will be zero.

Substitute, 0 m for $\mathrm{\u25b3}\lambda $ in the above expression.

$0m=\frac{h}{{m}_{e}c}(1-\mathrm{cos}\theta )\phantom{\rule{0ex}{0ex}}1-\mathrm{cos}\theta =0\phantom{\rule{0ex}{0ex}}\theta ={\mathrm{cos}}^{-1}(1)\phantom{\rule{0ex}{0ex}}={0}^{\circ}$

Thus, the scattering angle is ${0}^{\circ}$

Write the expression for the change in wavelength of the Compton effect.

$\mathrm{\u25b3}\lambda =\frac{h}{{m}_{e}c}(1-\mathrm{cos}\theta )$

Here, $\mathrm{\u25b3}\lambda $ is the change in waveleght, h is Plak's constant, me is mass of the electron and $\theta $ is scattering angle.

For the maximum change in frequency, the change in wavelength will be zero.

Substitute, 0 m for $\mathrm{\u25b3}\lambda $ in the above expression.

$0m=\frac{h}{{m}_{e}c}(1-\mathrm{cos}\theta )\phantom{\rule{0ex}{0ex}}1-\mathrm{cos}\theta =0\phantom{\rule{0ex}{0ex}}\theta ={\mathrm{cos}}^{-1}(1)\phantom{\rule{0ex}{0ex}}={0}^{\circ}$

Thus, the scattering angle is ${0}^{\circ}$

The velocity function is $$ for a particle moving along a line. What is the displacement (net distance covered) of the particle during the time interval [-3,6]?

How do velocity and acceleration differ?

A passenger plane made a trip to Las Vegas and back. On the trip there it flew 432 mph and on the return trip it went 480 mph. How long did the trip there take if the return trip took nine hours?

The position of an object moving along a line is given by $$. What is the speed of the object at $$?

A person observes fireworks displays from the safe distance of 0.750 meters. Assuming that the sound travels at 340 meters per second in air. What is the time between the person seeing the fireworks and hearing the explosion?

What is the speed of a rocket that travels 9000 meters in 12.12 seconds?

The distance between the earth and the moon is about 384,000 km. calculate the time it takes for light to travel from the moon to earth?

The velocity of the particle is given by v=3t^2+2t in m/s. The acceleration and displacement of the particle as a function of time respectively are...

The value of Planck's constant is $6.63\times {10}^{-34}$ js. The velocity of light is $3.0\times {10}^{8}m{s}^{-1}$. Which value is closest to the wavelength in nanometers of a quantum of light with frequencty of $8\times {10}^{15}{s}^{-1}$

1) $3\times {10}^{7}$

2) $2\times {10}^{-25}$

3) $5\times {10}^{-8}$

4) $4\times {10}^{1}$The transverse displacement y(x, t) of a wave on a string is given by $y(x,t)={e}^{(a{x}^{2}+b{t}^{2}+2\sqrt{ab}xt)}$. This represent:

A) wave moving in +x direction with speed $\sqrt{\frac{a}{b}}$

B) wave moving in +x direction with speed $\sqrt{\frac{b}{a}}$

C) standing wave of frequency $\sqrt{b}$

D) standing wave of frequency $\frac{1}{\sqrt{b}}$The mass of an electron is $9.1\times {10}^{-31}$ kg. If its K.E. is $3.0\times {10}^{-25}J$, calculate its wavelength.

A husband and wife take turns pulling their child in a wagon along a horizontal sidewalk. Each exerts a constant force and pulls the wagon through the same displacement. They do the same amount of work, but the husband's pulling force is directed ${58}^{o}$ above the horizontal, and the wife's pulling force is directed ${38}^{o}$ above the horizontal. The husband pulls with a force whose magnitude is 60 N. What is the magnitude of the pulling force exerted by his wife?

Can displacement be negative?

What is nodal plane and explain it's features

Mention the change in wave length of the photon after it collides with free electron?? Is the rule of particle can be applied here?