Question about random samplings and estimations. 100 students were selected to participate in a survey by the school in May 2013. The next month, another 100 students were randomly selected to participate in the same survey, out of which 2 had already participate in the survey the previous month. If the number of students did not change from May to June then what is the approximate number of students in the school? Came across this question. Is the question weird or am I just dumb? Can anyone suggest a way to solve this or an approach on how it can be solved. Thank you.

atarentspe

atarentspe

Answered question

2022-09-11

Question about random samplings and estimations.
100 students were selected to participate in a survey by the school in May 2013. The next month, another 100 students were randomly selected to participate in the same survey, out of which 2 had already participate in the survey the previous month. If the number of students did not change from May to June then what is the approximate number of students in the school?
Came across this question. Is the question weird or am I just dumb? Can anyone suggest a way to solve this or an approach on how it can be solved. Thank you.

Answer & Explanation

Salvador Howard

Salvador Howard

Beginner2022-09-12Added 12 answers

Suppose there are n students.
Number them with i=1,2,…,n and let Si take value 1 if student i is selected twice, and value 0 otherwise.
Note that:
E S i = P ( S i = 1 ) = ( 100 n ) 2
for every i.
If we set:
S := i = 1 n S i
then S is exactly the number of students that are chosen twice.
Taking its expectation by applying linearity of expectation we find:
E S = E i = 1 n S i = i = 1 n E S i = n ( 100 n ) 2 = 10000 n
The fact that exactly 2 students were chosen twice makes it reasonable to go for ES=2 which leads to n=5000.

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