Survey: prove 10% of population "Don't know"?I have a simple question that I expect is a standard situation, but I can't seem to find the right answer (maybe because it's too simple). I have a survey with the following answers: (What is your current risk tolerance for your personal investments?) Very Aggressive 1 Aggressive 11 Moderate 29 Conservative 7 Very Conservative 4 I don't know my risk tolerance 6 (total) 58 I want to be able to say something about the 6 "Don't know". I have tried to prove that 10% of the population "don't know", by using a chi-square test:

Dymnembalmese2n

Dymnembalmese2n

Answered question

2022-09-27

Survey: prove 10% of population "Don't know"?
I have a simple question that I expect is a standard situation, but I can't seem to find the right answer (maybe because it's too simple).
I have a survey with the following answers:
(What is your current risk tolerance for your personal investments?)
Very Aggressive 1
Aggressive 11
Moderate 29
Conservative 7
Very Conservative 4
I don't know my risk tolerance 6
(total) 58
I want to be able to say something about the 6 "Don't know". I have tried to prove that 10% of the population "don't know", by using a chi-square test:
Null hypothesis: 10% of the population "don't know"
yes no
expected: 52.2 5.8
observed: 52 6
Chi-square = (52-52.2)^2/52.2 + (6-5.8)^2/5.8 = 0.0077
Chi-square for a two-tailed 1-df test is 3.84
Since 0.0077 < 3.84 I cannot reject the null hypothesis and accept that 10% of the population "don't know".

Answer & Explanation

Rayna Aguilar

Rayna Aguilar

Beginner2022-09-28Added 14 answers

The fact that you failed to reject 10% does not mean that the true value is 10%. You could repeat the calculation for 9% and fail to reject that, too. If you do the calculation for 50% I predict you will be able to reject that. What you can do is find a region around 10% that you have a given desired confidence that the correct answer is within.
Check various percentages above 10 until the chi-square test gives 5% chance that the chi-square is worse. Say the break point is 23% (I am making this up-I didn't calculate it) Then do the same for the low end-maybe it is 3%. Then you can say that with 90% confidence the true value (under your assumption that the sample is representative, etc.) is in the range 3%−23%

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