A space X is unicoherent if whenever A,B are closed connected subsets of X such that A∪B=X, their intersection A∩B is connected. The survey "A Survey on Unicoherence and Related Properties" by Garcia-Maynez and Illanes says that intuitively, a unicoherent space is a space with no "holes". For example, the closed disk in the plane is unicoherent, but the circle S1 is not. This sounds like simple connectedness. For simple connectedness, by van Kampen's theorem, we have the following: if a space X has simply connected open subsets U,V such that U∪V=X and U∩V is nonempty and path-connected, then X is simply connected. It is then natural to ask a similar question for unicoherence. So, my question is: if a space X has closed unicoherent subsets A,B such that A∪B=X and A∩B is connected, is X nece

Meldeaktezl

Meldeaktezl

Answered question

2022-09-30

A space X is unicoherent if whenever A,B are closed connected subsets of X such that A B = X, their intersection A Bis connected. The survey "A Survey on Unicoherence and Related Properties" by Garcia-Maynez and Illanes says that intuitively, a unicoherent space is a space with no "holes". For example, the closed disk in the plane is unicoherent, but the circle S 1 is not. This sounds like simple connectedness. For simple connectedness, by van Kampen's theorem, we have the following: if a space X has simply connected open subsets U,V such that U V = X and U V is nonempty and path-connected, then X is simply connected. It is then natural to ask a similar question for unicoherence. So, my question is: if a space X has closed unicoherent subsets A,B such that A B = X and 𝐴 𝐵 is connected, is X necessarily unicoherent? If necessary, you can assume that A,B are open rather than closed, or replace unicoherence conditions with open unicoherence conditions. Also, you can assume that 𝐴 𝐵 is nonempty if needed. Thank you in advance!

Answer & Explanation

Peutiedw

Peutiedw

Beginner2022-10-01Added 9 answers

If X is compact and metric (or only Hausdorff) and 𝐴 𝐵 is connected and locally connected, then X is unicoherent. You can search for the paper 'Special Unions of Unicoherent Continua'. But if 𝐴 𝐵 is connected and not locally connected, then X is not necessarily unicoherent.

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