Annette Arroyo

2020-10-18

Three identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force $\overrightarrow{F}$ The magnitude of the tension in the string between blocks B and C is T=3.00N. Each block has mass m=0.400kg.

What is the magnitude F of the force?

What is the tension in the string between block A and block B?

Ezra Herbert

Skilled2020-10-19Added 99 answers

The magnitude of F of the force

T=ma

$3.00N=0.400kg\cdot a$

thus

$a=7.5\text{}\frac{m}{{s}^{2}}$

However, this only represents the overall acceleration; for each separate block, the

$a=\frac{7.5}{2}=3.75\text{}\frac{m}{{s}^{2}}$

F can now be find by using

$a=\frac{F}{3m}$ and solving for F

$F=a\cdot 3m$

$F=4.5N$

For the Tension between block A and B, all we do is

T=ma, knowing that $a=3.75\text{}\frac{m}{{s}^{2}}$ for each block.

$T=\left(0.400\text{}kg\right)\left(3.75\text{}\frac{m}{{s}^{2}}\right)=1.5N$

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