pogonofor9z

2022-01-03

A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. The amplitude of the motion is 0.240 m and the period is 3.08 s.

What is the acceleration of the block when x = 0.160 m?

usaho4w

Beginner2022-01-04Added 39 answers

The maximum speed of the block at time T,

The placement of the block,

$T=3.08\text{}s$

$x=0.160\text{}m$

The angular frequncy,

The speed of the block,

$\omega =\frac{2\pi}{T}$

$\alpha =-{\omega}^{2}x$

The speed of the block when x=0.160 m,

$\alpha ={(-\frac{2\pi}{3.08\text{}s})}^{2}\times 0.160\text{}m$

$={(-2.039\text{}ra\frac{d}{s})}^{2}\times 0.160\text{}m$

$=0.665\text{}\frac{m}{{s}^{2}}$

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