If 2 × 10 5 J of heat is required to melt 4 kg of a solid at its melting point of 70 ∘ in 10 minutes. What is the specific latent heat of fusion of the solid?

Explained: "If 2 × 10 5 J of heat..."

Dorstadt4uz

2022-12-20

2 \times 10^{5}

J of heat is required to melt 4 kg of a solid at its melting point of

70^{\circ}

in 10 minutes. What is the specific latent heat of fusion of the solid?

Mauricio Liu

Beginner2022-12-21Added 6 answers

Given data:
heat

a = 2 \times 10^{5} J

mass M=4 kg
70 C in 10 minutes
Solution:
L=specific latent heat of fusion
We know that

Q = M \cdot L L = \frac{Q}{M} = \frac{2 \times 10^{5}}{4} = 50000 J / k g L = 50 K J / k g

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