Step by step solution to "What mass of steam at 100∘C must be..."

belandong0ir

Answered question

2023-01-04

What mass of steam at

100^{\circ} C

must be mixed with

150 g

of ice at its melting point, in a thermally insulated container to produce water of

50^{\circ} C

iJehovazhk

Beginner2023-01-05Added 8 answers

X grams of steam should be used. As latent heat of steam to water is 533 calories per gram, when it converts to water at

50^{\circ} C

, it looses heat given by

533 x + 50 x = 583 x

and as latent heat of ice to water is 80 calories per gram, when it converts to water at

50^{\circ} C

, it gains heat given by

150 \times 80 + 150 \times 50 = 12000 + 7500 = 19500

Thus, we must have

583 x = 19500

- assuming that there is no loss of heat to environment and
Then

x = \frac{19500}{583} = 33.45 g

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