Calculate delta G and delta A for the freezing of 1.00 mol of H2O at 0oC and 1 atm. The heat of fusi

Laila Andrews

Laila Andrews

Answered question

2022-04-06

Calculate delta G and delta A for the freezing of 1.00 mol of H2O at 0oC and 1 atm. The heat of fusion of water at 0oC is 6002 J mol-1. The density of ice at 0oC and 1 atm is 0.917 g cm-3, and that of water at the same conditions is 1.000 g cm-3.
The correct answers are 0; -0.16 respectively but i'm getting a different one

Answer & Explanation

Cristal Obrien

Cristal Obrien

Beginner2022-04-07Added 16 answers

In the above problem we need to calculate, the change in Gibbs free energy ( GG) and change in Helmholtz ( AA) free energy for freezing of 1 mol of H20 at 0 C and 1 atm
Given,
ρ ice = 0.917 g / c m 3 ρ water = 1 g / c m 3
Now, at 0°C, water and ice are in equilibrium, since that is the freezing point of water. At equilibrium the free energy change associated with the process = 0
i.e., G for freezing of water at 0°C and 1 atm
This can also be proved mathematically as:
Given H = 6002   J / m o l and we know S = H fusion / T = 6002 / 273
G = H T S = 6002 ( J m o l ) ( 273 ( K ) × 6002 J / m o l 273 K = 0
Now, we know that G and A are related to each other by,
G = A + ( P V )
Now, P VV can be calculated as:
10 5 P a ( 1 ρ water 1 ρ ice ) × 1 c m 3 10 6 m 3 × 18.015 ( g l m o l ) = 0.16 J / m o l
Therefore A = 0.16 J / m o l

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