A new linear temperature scale, degrees Zunzol ( ∘ Z ), is based on the freezing point and boiling point of a newly discovered compound zunzol. The freezing point of zunzol − 117.3 ∘ C, is defined as 0 ∘ Z, and the boing point of zunzol, 78.4 ∘ C is defined as 100 ∘ Z. What is the freezing point of water in degrees Zunzol?

Question

A new linear temperature scale, degrees Zunzol       (    ∘    Z  ), is based on the freezing point and boiling point of a newly discovered compound zunzol. The freezing point of zunzol   −      117.3    ∘    C, is defined as       0    ∘    Z, and the boing point of zunzol,       78.4    ∘    C is defined as       100    ∘    Z. What is the freezing point of water in degrees Zunzol?

hospitaliapbury · Accepted Answer

The freezing point of zunzol is       0    ∘    Z  =  −      117.3    ∘    CThe boiling point of zunzol is       100    ∘    Z  =      78.4    ∘    CStandard values:The freezing point of water is       0    ∘  The boiling point of water is       100    ∘  Calculate the freezing point of water in           ∘    ZThe freezing point of water   =      0    ∘    C    =  (  0  +  117.3      )    ∘    Z    =      117.3    ∘    ZHence the freezing point of water in       117.3    ∘    ZCalculate the boiling point of water in           ∘    ZThe boiling point of water   =      100    ∘    C    =  (  100  +  117.3      )    ∘    Z    =      217.3    ∘    ZHence the boiling  point of water in       217.3    ∘    Z

Don Sumner · Accepted Answer

Answer:59.92 degreesExplanation:Let&#039;s denote the freezing point of water in degrees Celsius as TC and the freezing point of water in degrees Zunzol as TZ. We are given that the freezing point of zunzol is -117.3 degrees Celsius, defined as 0 degrees Zunzol (TC=−117.3∘C and TZ=0), and the boiling point of zunzol is 78.4 degrees Celsius, defined as 100 degrees Zunzol (TC=78.4∘C and TZ=100).We can set up a proportion to convert between the two temperature scales:TC−TCfzTCbz−TCfz=TZ−TZfzTZbz−TZfzwhere TCfz and TCbz are the freezing and boiling points of zunzol in degrees Celsius, and TZfz and TZbz are the freezing and boiling points of zunzol in degrees Zunzol.Substituting the known values:TC−(−117.3)78.4−(−117.3)=TZ−0100−0Simplifying:TC+117.3195.7=TZ100To find the freezing point of water in degrees Zunzol (TZ), we need to substitute TC with the freezing point of water in degrees Celsius. The freezing point of water in degrees Celsius is 0 degrees Celsius.0+117.3195.7=TZ100Simplifying further:117.3195.7=TZ100To find TZ, we can cross-multiply:TZ=117.3×100195.7Calculating the value:TZ≈59.92Therefore, the freezing point of water in degrees Zunzol is approximately 59.92 degrees Zunzol.

Vasquez · Accepted Answer

To solve this problem, we need to find the equivalent temperature in degrees Zunzol for the freezing point of water.Let&#039;s denote the freezing point of water in degrees Zunzol as TZ. We know that the freezing point of zunzol is defined as 0 degrees Z, and the freezing point of zunzol in Celsius is -117.3 degrees C. We also know that the boiling point of zunzol is defined as 100 degrees Z, which corresponds to 78.4 degrees C.To find the freezing point of water in degrees Zunzol, we can set up a proportion using the Celsius temperature scale:TZ−0100−0=0−(−117.3)100−78.4Simplifying this equation:TZ100=117.321.6Cross-multiplying:TZ=117.3×10021.6Calculating the value:TZ≈542.5Therefore, the freezing point of water in degrees Zunzol is approximately 542.5 degrees Z.

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