Calculate how much energy (kJ) is required to heat a liter of water from 30 ∘ C to saturated liquid at normal boiling point

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Calculate how much energy (kJ) is required to heat a liter of water from       30    ∘    C to saturated liquid at normal boiling point

erlanpb8cj · Accepted Answer

Given data:Assume, mass of liquid = 1 kgTemperature of water T1 = 30 C = 303 KNormal boiling point of water Tb = 373 KSpecific heat of water = 4.2 KJ/KgKFind the energy required to heat water from 30 C to normal boiling point.Energy required to heat water from 30 C to normal boiling point  Q  =  m      C    p    (      T    b    −      T    1    )Where, m=mass of water      C    p   = specific heat of water      T    b   = boiling point of water      T    1   = initial temperature  Q  =  1     k  g  ⋅  4.2     K  J      /    K  g  G  ⋅  (  37.3  −  30.3  )    =  294     K  JSo, heat required is 294 KJ.

Calculate how much energy (kJ) is required to heat a

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