A rigid tank initially contains saturated vapor at 0,35 MPa. Then heat transferred to water until its temperature is 400 ∘ C. Determine the heat transfer during this process, in kJ/kg.

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A rigid tank initially contains saturated vapor at 0,35 MPa. Then heat transferred to water until its temperature is       400    ∘    C. Determine the heat transfer during this process, in kJ/kg.

bardalhg · Accepted Answer

Saturation Pressure: The pressure exerted by the vapor on the liquid when both liquid and vapor are in equilibrium is known as saturation pressure. the corresponding temperature is known as the saturation temperature.First Law of thermodynamics: The first law of thermodynamics states that Energy can never be created nor be destroyed but it can be transferred from one form to another form.First law of thermodynamics is given by formula dQ = dU + WdQ is the heat added or rejecteddU is the change in internal energy W is the work doneGiven data: The initial pressure of the saturated vapor       P    1    =  0.35   MPaAt 0.35 MPa from saturated water steam tables The specific internal energy of saturated vapour is given by       u    g    =      u    1    =  2548.5   kJ/kgThe saturated vapour is heated until the temperature reaches       T    2    =      400    ∘    CFrom superheated steam tables at 0.35 Mpa and       400    ∘    CThe specific internal energy of the vapour is given by       u    2    =  2965.4   kJ/kgFrom the first law of thermodynamics The heat transferred is given by   Q  =  △  U  +  P  △  VHere volume of the vessel is constant so   △  V  =  0  Q  =      u    2    −      u    1      =  2965.4  −  2548.5    =  416.9      kJ/kg

A rigid tank initially contains saturated vapor at 0,35 MPa. Then heat transferred to water until its temperature is 400°C. Determine the heat transfer during this process, in kJ/kg.

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