Darryl English

2022-07-14

A rigid tank initially contains saturated vapor at 0,35 MPa. Then heat transferred to water until its temperature is ${400}^{\circ}C$. Determine the heat transfer during this process, in kJ/kg.

bardalhg

Beginner2022-07-15Added 15 answers

Saturation Pressure: The pressure exerted by the vapor on the liquid when both liquid and vapor are in equilibrium is known as saturation pressure. the corresponding temperature is known as the saturation temperature.

First Law of thermodynamics: The first law of thermodynamics states that Energy can never be created nor be destroyed but it can be transferred from one form to another form.

First law of thermodynamics is given by formula

dQ = dU + W

dQ is the heat added or rejected

dU is the change in internal energy

W is the work done

Given data: The initial pressure of the saturated vapor ${P}_{1}=0.35\text{MPa}$

At 0.35 MPa from saturated water steam tables

The specific internal energy of saturated vapour is given by

${u}_{g}={u}_{1}=2548.5\text{kJ/kg}$

The saturated vapour is heated until the temperature reaches ${T}_{2}={400}^{\circ}C$

From superheated steam tables at 0.35 Mpa and ${400}^{\circ}C$

The specific internal energy of the vapour is given by

${u}_{2}=2965.4\text{kJ/kg}$

From the first law of thermodynamics

The heat transferred is given by

$Q=\mathrm{\u25b3}U+P\mathrm{\u25b3}V$

Here volume of the vessel is constant so $\mathrm{\u25b3}V=0$

$Q={u}_{2}-{u}_{1}\phantom{\rule{0ex}{0ex}}=2965.4-2548.5\phantom{\rule{0ex}{0ex}}=416.9\text{}\text{kJ/kg}$

First Law of thermodynamics: The first law of thermodynamics states that Energy can never be created nor be destroyed but it can be transferred from one form to another form.

First law of thermodynamics is given by formula

dQ = dU + W

dQ is the heat added or rejected

dU is the change in internal energy

W is the work done

Given data: The initial pressure of the saturated vapor ${P}_{1}=0.35\text{MPa}$

At 0.35 MPa from saturated water steam tables

The specific internal energy of saturated vapour is given by

${u}_{g}={u}_{1}=2548.5\text{kJ/kg}$

The saturated vapour is heated until the temperature reaches ${T}_{2}={400}^{\circ}C$

From superheated steam tables at 0.35 Mpa and ${400}^{\circ}C$

The specific internal energy of the vapour is given by

${u}_{2}=2965.4\text{kJ/kg}$

From the first law of thermodynamics

The heat transferred is given by

$Q=\mathrm{\u25b3}U+P\mathrm{\u25b3}V$

Here volume of the vessel is constant so $\mathrm{\u25b3}V=0$

$Q={u}_{2}-{u}_{1}\phantom{\rule{0ex}{0ex}}=2965.4-2548.5\phantom{\rule{0ex}{0ex}}=416.9\text{}\text{kJ/kg}$

What is the work for the free expansion of a gas into vacuum?

How to convert ${45}^{\circ}\text{}C$ to Fahrenheit?

The temperature of melting ice is______________$\xb0C$=________________$\xb0F$. A$0$ B$32$

What is the effect of an increase in pressure on the boiling point of a liquid?

Warm Water freezes faster than cold water. Why?

What is the SI unit of specific heat capacity?

16 degrees celsius is what in fahrenheit?

If the boiling point of water in Kelvin scale is 373 K. What is the boiling point of water on degree celcilus scale(oC)?

Which of the following is/are an example of the convection of heat?

A rod is being heated from one side

Boiling water

Sunlight reaching earth

Ladle is getting hot in soupWhat is the freezing point of water?

How to solve $|3x+6|>15$?

How does heat travel through empty space?

What is the equivalent temperature of 0 degree Celsius in Fahrenheit scale? A)-32 degree Celsius;B)64 degree Celsius; C)32 degree Celsius; D)16 degree Celsius

$1c{m}^{3}$ of water at its boiling point absorbs 540 calories of heat to become steam with a volume of $1671c{m}^{3}$. If the atmospheric pressure is $1.013\times {10}^{5}N/{m}^{2}$ and the mechanical equivalent of heat = 4.19 J/calorie, the energy spent in this process in overcoming intermolecular forces is

A) 540 calorie

B) 40 calorie

C) 500 calorie

D) ZeroHow to convert 53 celsius to fahrenheit?