What is the physical meaning of W[J]=ℏ/i lnZ[J]?

wendi1019gt

wendi1019gt

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2022-08-15

What is the physical meaning of W [ J ] = i ln Z [ J ]

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vibrerentb

vibrerentb

Beginner2022-08-16Added 21 answers

Recall that, by definition,
Z [ J ] = e i W [ J ] = Ω | e i H T | Ω
where H is the Hamiltonian of your system, and Ω is the vacuum state. Therefore, W [ J ] can be interpreted as the energy of the vacuum E Ω in the presence of a source J, where the origin is chosen at E=0 for J=0. In other words, W[J] is how much more energy does the vacuum have when we turn on an external source J.
More precisely, and as per Z [ J ] = e i W [ J ] , you can think of W as the Helmholtz free energy of the system.

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