Why does U=TS−PV+sum_i μ_iNi?

saillantpq

saillantpq

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2022-08-27

Why does U = T S P V + i μ i N i

Answer & Explanation

arbustekp

arbustekp

Beginner2022-08-28Added 8 answers

I'm going to suppress the sum over different chemical potentials for simplicity as it doesn't materially affect the argument. If we write U as a function of S,V,N, then extensivity of U is mathematically defined as follows
U ( λ S , λ V , λ N ) = λ U ( S , V , N )
Physically, this is saying that if you scale the quanities that characterize your physical system by a certain amount, then the energy scales by the same amount. The mathematical terminology for this is that U is a homogeneous function of degree 1 in S, V, and N. Now, there is a theorem on homogeneous functions called Euler's homogeneous function theorem which (up to a technical assumption or two) states that a function f : R n R is homogeneous of degree k>0, namely
f ( λ x ) = λ k f ( x )
if and only if
k f ( x ) = x f ( x )
Since the energy is a homogeneous function of degree 1, this theorem tells us that
U ( S , V , N ) = ( S , V , N ) U ( S , V , N ) = S ( U S ) V , N + V ( U V ) S , N + N ( U N ) S , V
On the other hand, the fundamental thermodynamic relation you wrote (as the first equation) above allows us to identify
( U S ) V , N = T ( U V ) S , N = P ( U N ) S , V = μ
so that we get the desired result:
U ( S , V N ) = T S P V + μ N

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