Solve the laplace inverse:Solve the differential equation y''+2y'+17y=0,

Answered question

2022-04-19

Solve the laplace inverse:

Solve the differential equation y''+2y'+17y=0, y(0) and y'(0)=12

Answer & Explanation

RizerMix

RizerMix

Expert2023-04-28Added 656 answers

We are given the differential equation:
y+2y+17y=0
and the initial conditions y(0) and y(0)=12.
To solve this differential equation, we can first find the characteristic equation by assuming that y=ert, where r is a constant. Substituting this assumption into the differential equation gives:
r2ert+2rert+17ert=0
Dividing both sides by ert gives:
r2+2r+17=0
Solving this quadratic equation for r gives:
r=1±4i
Therefore, the general solution to the differential equation is:
y(t)=c1etcos(4t)+c2etsin(4t)
where c1 and c2 are constants that we need to determine using the initial conditions.
Using the first initial condition y(0), we have:
y(0)=c1cos(0)+c2sin(0)=c1
Therefore, we know that c1=y(0).
Using the second initial condition y(0)=12, we have:
y(0)=c1+4c2=12
Solving for c2 gives:
c2=c1+34
Substituting this expression for c2 into the general solution gives:
y(t)=y(0)etcos(4t)+y(0)+34etsin(4t)
Therefore, the solution to the differential equation with the given initial conditions is:
y(t)=y(0)etcos(4t)+y(0)+34etsin(4t)

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