Sand falls from a conveyor belt at the rate of 10 (m^3)/(min) onto the top of s conical pile. The height of the pile is always three-eighths of the base diameter. How fast is the radius changing when the pile is 4 m high? Give your answer in cm/min,

Guabellok4

Guabellok4

Open question

2022-08-20

Sand falls from a conveyor belt at the rate of 10m3min onto the top of s conical pile. The height of the pile is always three-eighths of the base diameter. How fast is the radius changing when the pile is 4 m high? Give your answer in cm/min,

Answer & Explanation

elverku7

elverku7

Beginner2022-08-21Added 9 answers

Step 1
Diameter is 2r.
Given: rate of volume increase and relationship between h an r.
We're looking for dhdt when h=4. Plug in h=4 to find r at the same moment for use later.
dVdt=10
h=38(2r)=34r
(4)=34r
r=434=163
Step 2
V=13πr2h
=13πr2(3r4)
=14πr3
dVdt=34πr2drdt
Step 3
Plug in the values for r and dVdt to solve.
34πr2drdt=dVdt
34π(163)2drdt=10
drdt=10364π
=1532πmmin100cm1m
=150032πcmmin=3758πcmmin
14.92cmmin
Hollywn

Hollywn

Beginner2022-08-22Added 1 answers

Step 1
A dameter is difened as 2 times the redius d=2r
PSKUse the given relationship between h and r to get the cone volume equation V all in terms of h.
h=38d=38(2r)=34r
r=43h
V=13πr2h
=13π(43h)2h
=1627πh3
Step 2
Implicitly differentiate V with respect to time
dVdt=(3)1627πh2dhdt
Step 3
Substitute the given values
dVdt=10
h=4
and solve for dhdt
1m=100cm
10=169π(4)2dhdt
dhdt=109256π
=45128πmmin
=4500128πcmmin=112532πcmmin
11.19

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