scherezade29pc

2022-07-23

What is the period of $f(t)=\mathrm{sin}(\frac{t}{36})+\mathrm{cos}(\frac{t}{9})$?

Franklin Frey

Beginner2022-07-24Added 15 answers

The period for both $\mathrm{sin}$ kt and $\mathrm{cos}$ kt is $2\frac{\pi}{k}$

The period of $\mathrm{sin}(\frac{t}{36})=72\pi $

The period of $\mathrm{cos}(\frac{t}{9})=18\pi $

18 is a factor of 72.

So, the period for the compounded oscillation is $72\pi $

The period of $\mathrm{sin}(\frac{t}{36})=72\pi $

The period of $\mathrm{cos}(\frac{t}{9})=18\pi $

18 is a factor of 72.

So, the period for the compounded oscillation is $72\pi $

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