A particle of mass 10kg is placed in potential field given by V = ( 50 x 2 + 100 ) erg/g. What will be frequency of oscillation of particle ?

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A particle of mass 10kg is placed in potential field given by   V  =  (  50      x          2        +  100  ) erg/g. What will be frequency of oscillation of particle ?

Alaina Mcintosh · Accepted Answer

For a conservative force acting, relation between potential energy and force is given as   F  =  −            d      U              d      x       (here, given, V=potential, so V*m=U= potential energy  =  10000  (  50      x          2        +  100  ), see the unit)So, differentiating the given equation,we get,F=-100*10000x or,       F    m    =  −  100  ∗      10000    10000    x  =  −  100  xNow, in case of a particle in S.H.M force equation is given as,       F    m    =  −      ω          2        xSo,comparing the obtained force equation,we get,   ω  =      100   i.e   10            r      a      d        s  This is the angular frequency.So,   ν  =      ω          2      π        =  1.6      s          −      1

A particle of mass 10kg is placed in potential field given by V = (50x^2 + 100) erg/g. What will be frequency of oscillation of particle ?

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