A point source emits sound waves isotropically. The intensity of the waves 6.00 m from the source is 4.50 × 10 − 4 W / m 2 Assuming that the energy of the waves is conserved, find the power of the source.

Question

A point source emits sound waves isotropically. The intensity of the waves 6.00 m from the source is  4.50  ×      10          −      4        W      /        m          2      Assuming that the energy of the waves is conserved, find the power of the source.

Marley Abbott · Accepted Answer

Given:The distance from the source:r=6.00mThe intensity of the source:  I  =  4.50  ∗      10          −      4            W          m              2            The equation for the power is:P=IAwhere I is the intensity of the sound, while A is the area.Considering that the sound source is sending waves isotropically, we can consider the area as a sphere, and type the equation for it as:  A  =  4  π      r          2      where r is given to us in the assignment.Putting the equation for the area back in the equation for the power, we get:  P  =  I  4  π      r          2      And all that is left now is to exchange the values and calculate the power.  P  =  4.5  ∗      10          −      4        ∗  4  ∗  π  ∗      6          2      P=0.2WResult:P=0.2W

A point source emits sound waves isotropically. The intensity of the waves 6.00 m from the source is 4.50*10^(−4)W/m^2 Assuming that the energy of the waves is conserved, find the power of the source.

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