Parker Pitts

2022-10-03

When a sound wave travels directly toward a hard wal, the incoming and rerlected waves can combine to produce a standing wave. There is an antinode right at the wall, just as at the end of a closed tube, so the sound near the wall is loud. You are standing beside a brick wall listening to a 50 Hz tone from a distant loudspeaker. How far from the wall must you move to find the first quiet spot? Assume a sound speed of 340 m/s.

ordonansexa

To solve this problem, we will be applying an equation that determines the wavelength of the wave:
$\lambda =\frac{v}{f}$
Where: $\lambda$ - wavelength v-wave speed f-frequency
Also, we will be applying the following equation that determines the distance of the first quiet spot:
$d=\frac{\lambda }{4}$
Where: d-distance $\lambda$ - wavelength
First, we will put known values into the equation that determines the wavelength and calculate it as:
$\lambda =\frac{340\frac{m}{s}}{50Hz}$
=6.8m
Next, we will put known values into the equation that determines distance and calculate it:
$d=\frac{6.8m}{4}$
=1.7m
Result:
d=1.7m

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