Damon Vazquez

2022-09-30

What is the intensity of a sound which has a sound level of 35 dB?

seppegettde

Beginner2022-10-01Added 7 answers

You can use the relationship:

$I(dB)=10\mathrm{log}(\frac{I}{{I}_{0}})$

Where ${I}_{0}={10}^{-12}\frac{W}{{m}^{2}}$ represents the intensity just audible (correspnding to 0dB).

So:

$35=10\mathrm{log}(\frac{I}{{10}^{-12}})$; power 10 both sides and rearrange:

$I=3.2\times {10}^{-9}\frac{W}{{m}^{2}}$

$I(dB)=10\mathrm{log}(\frac{I}{{I}_{0}})$

Where ${I}_{0}={10}^{-12}\frac{W}{{m}^{2}}$ represents the intensity just audible (correspnding to 0dB).

So:

$35=10\mathrm{log}(\frac{I}{{10}^{-12}})$; power 10 both sides and rearrange:

$I=3.2\times {10}^{-9}\frac{W}{{m}^{2}}$

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