Best solutions to - "What is the frequency of the second harmonic..."

Nathanial Levine

Answered question

2022-09-05

What is the frequency of the second harmonic sound wave in an open-ended tube that is 4.8 m long? The speed of sound in air is 340 m/s.

goffaerothMotw1

Beginner2022-09-06Added 10 answers

For an open ended tube, both the ends represent antinodes,so distance between two antinodes

= \frac{λ}{2}

(where ,

λ

is the wavelength)
So,we can say

l = \frac{2 λ}{2}

for 2 nd harmonic,where l is the length of the tube.
So,

λ = l

Now,we know,

v = ν λ

where, v is the velocity of a wave,

ν

is the frequency and

λ

is the wavelength.
Given,

v = 340 m s^{- 1}, l = 4.8 m

So,

ν = \frac{v}{λ} = \frac{340}{4.8} = 70.82 H z

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