Four mass–spring systems oscillate in simple harmonic motion. Rank the periods of oscillation for the mass–spring systems from largest to smallest. m = 2 kg , k = 2 N/m m = 2 kg , k = 4 N/m m = 4 kg , k = 2 N/m m = 1 kg , k = 4 N/m

Jayden Davidson

Jayden Davidson

Answered question

2022-12-19

Four mass–spring systems oscillate in simple harmonic motion. Rank the periods of oscillation for the mass–spring systems from largest to smallest.
m = 2 k g , k = 2 N / m m = 2 k g , k = 4 N / m m = 4 k g , k = 2 N / m m = 1 k g , k = 4 N / m

Answer & Explanation

ZoogTraigngerl4e

ZoogTraigngerl4e

Beginner2022-12-20Added 4 answers

The periods of oscillation for the mass–spring systems from largest to smallest is:
1. m = 4 k g , k = 2 N / m ( T = 8.89 s ) 2. m = 2 k g , k = 2 N / m ( T = 6.28 s ) 3. m = 2 k g , k = 4 N / m ( T = 4.44 s ) 4. m = 1 k g , k = 4 N / m ( T = 3.14 s )
Explanation:
The time it takes for an object in simple harmonic motion to complete one vibration is defined as the following equation:
T = 2 π m k
Where:
T = period of oscillation
m = inertia mass of the oscillating body
k = spring constant
m = 2 k g , k = 2 N / m
T = 2 π 2 2 T = 2 π T = 6.28 s
m = 2 k g , k = 4 N / m
T = 2 π 2 4 T = 2 π 1 2 T = 4.44 s
m = 4 k g , k = 2 N / m
T = 2 π 4 2 T = 2 π 2 T = 8.89 s
m = 1 k g , k = 4 N / m
T = 2 π 1 4 T = π T = 3.14 s
Therefore the rank the periods of oscillation for the mass–spring systems from largest to smallest is:
1. m = 4 k g , k = 2 N / m ( T = 8.89 s ) 2. m = 2 k g , k = 2 N / m ( T = 6.28 s ) 3. m = 2 k g , k = 4 N / m ( T = 4.44 s ) 4. m = 1 k g , k = 4 N / m ( T = 3.14 s )

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