The electrons in a particle beam each have a kinetic energy of 1.6 × 10 − 7 J. What are the magnitude and direction of the electric field that stops these electrons in a distance of 10.0cm A. 10 3 v / m in the direction of velocity of electrons B. 10 3 v / m positive direction of velocity of electrons C. 10 3 v / m perpendicular to velocity of electrons D. 10 6 v / m perpendicular to velocity of electrons

Question

The electrons in a particle beam each have a kinetic energy of   1.6  ×      10          −      7        J. What are the magnitude and direction of the electric field that stops these electrons in a distance of 10.0cm A.       10    3    v      /    m in the direction of velocity of electrons     B.       10    3    v      /    m positive direction of velocity of electrons C.       10    3    v      /    m perpendicular to velocity of electrons D.       10    6    v      /    m perpendicular to velocity of electrons

Jewel Kelly · Accepted Answer

W = FS      1    2    m      v    2    =  E  q  S  1.6  ×      10          −      17        =  E  ×  1.6  ×      10          −      19        ×  10  ×      10          −      2        E  =      10    3    V      /    m in the direction of velocity of electrons

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