A particle is moving along the x-axis with its coordinate with the time t given by x(t)=−3t^2+8t+10 meter. Another particle is moving along the y-axis with its coordinate as a function of time given by y(t)=5−8t^3 meter. . At t=1 second , the speed of the second particle as measured in the frame of the first particle is given as sqrt v . Then v(ms^−1) is

inhaltynuaddyh4b

inhaltynuaddyh4b

Answered question

2023-02-11

A particle is moving along the x-axis with its coordinate with the time t given by x(t)=-3t2+8t+10meter. Another particle is moving along the y-axis with its coordinate as a function of time given by y(t)=5-8t3meter. . At t=1 second , the speed of the second particle as measured in the frame of the first particle is given as v . Then v(ms-1) is

Answer & Explanation

Gazzuolabps

Gazzuolabps

Beginner2023-02-12Added 10 answers

The velocity of particles A
v A = v x = d x d t = = ( 6 t + 8 ) o r v A t = 1 = ( - 6 + 8 ) = 2 m s - 1
v A = + 2 i ^ m s - 1
The velocity of particles B
v B = v y = d y d t = ( - 24 t 2 ) o r v B t = 1 = ( - 24 ) m s - 1
v B = - 24 j ^ m s - 1
Speed of the particle B with respect to A,
v B A = ( v B - v A ) = ( - 24 j ^ - 2 i ^ ) = ( - 2 i ^ - 24 j ^ )
The magnitude of the velocity
| v B A | = ( 2 ) 2 + ( 24 ) 2
| v B A | = v v = 580 v = 580 m s - 1

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