Expansion of a gas in vacuum is called free expansion. Calculate the work done and the change in internal energy when 1 liter of ideal gas expands isothermally into vacuum unit its total volume is 5 litre?

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unieventos8l9 · Accepted Answer

Work done in vacuum is calculated by:  w  =  −      P          ext        (      V          final        −      V          initial        )For the given problem:       P          ext        =  0, because it is a free expansion (in the vacuum).Hence,  w  =  −  (  0  ×  (  5  −  1  )  )    w  =  0According to joule experimental observation, For an isothermal expansion of ideal gas, no heat will be absorbed or evolved, hence q=0.By the 1st law of thermodynamics,  q  +  w  =  △  U    △  U  =  0Since, w=0 and q=0, then the change in internal energy   △  U will also be 0.

Expansion of a gas in vacuum is called free expansion. Calculate the work done and the change in internal energy when 1 liter of ideal gas expands isothermally into vacuum unit its total volume is 5 litre?

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