Expert answers to "A 45-g piece of ice at 0 degree..."

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Advanced Physics

smileycellist2

Answered question

2021-03-23

A 45-g piece of ice at 0 degree C is added to a sample of water at 8 degrees C. All of the ice melts and the temperature of the water decreases to 0 degree C. How many grams of water were there in the sample?

Answer & Explanation

tabuordg

Skilled2021-03-25Added 99 answers

Understand that once the ice melts, all you have is water at

0^{\circ} C

. That means the water cools from

8^{\circ} C

0^{\circ} C

and the heat absorbed by the ice was enough for it to melt.

q = mass \times heat of fusion

the heat of fusion for water is 333J/g
q = (45 g)(333 J/g)
q = 14985 J
Now that you have the heat released by the water, use

q = m c △ T

14985 = m (4.18 \frac{J}{g^{\circ}} C) (8^{\circ} C - 0^{\circ} C)

m=448.12 g mass of water

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