A 83.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 34.0 m/s. If both are initially at rest and if the ice is frictionless, how far (in m) does the player recoil in the time it takes the puck to reach the goal 21.0 m away? (Enter the magnitude.)

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Payton Mcbride · Accepted Answer

Solution:By momentum convervation   (  ∵      f          n      e      t        =  0   in   x  −  d  i  r  )      P    i    =      P    f    0  =  83  ×  v  (  speed of player  )  +  0.150  ×  34v=-0.0614 m/s-ve means opposite of ball which makes sensetime taken by puck(t)  =      distance    speed    t  =      21.0    34.0  t=0.6176 sdistance covered by player in same time-interval(d)= speed times time  d  =  0.0614  ×  0.6176d=0.0379 m

A 83.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 34.0 m/s. If both are initially at rest and if the ice is frictionless, how far (in m) does the player recoil in the time it takes the puck to reach the goal 21.0 m away?

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