Two boats start together and race across a 60-km-wide lake and back. Boat A goes across at 60 km/h and returns at 60 km/h. Boat B goes across at 30 km/h, and its crew, realizing how far behind it is getting, returns at 90 km/h. Turnaround times are negligible, and the boat that completes the round trip first wins

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user_27qwe · Accepted Answer

To solve the given problem, let&#039;s analyze the situation and compare the times taken by Boat A and Boat B to complete the round trip.Let&#039;s denote the time taken for Boat A to cross the lake as tA and the time taken for Boat B to cross the lake as tB.For Boat A:- Time taken to cross the lake: tA=60km60km/h=1hour (since the speed is constant at 60 km/h).- Time taken to return: tA=60km60km/h=1hour (since the speed is constant at 60 km/h).Therefore, Boat A takes a total of ttotal,A=tA+tA=1hour+1hour=2hours to complete the round trip.For Boat B:- Time taken to cross the lake: tB=60km30km/h=2hours (since the speed is constant at 30 km/h).- Time taken to return: tB=60km90km/h=23hours (since the speed is constant at 90 km/h).Therefore, Boat B takes a total of ttotal,B=tB+tB=2hours+23hours=83hours to complete the round trip.Comparing the total times, we find that ttotal,A=2hours and ttotal,B=83hours. Since 2hours&amp;lt;83hours, Boat A completes the round trip in a shorter time.Therefore, Boat A wins the race.

Two boats start together and race across a

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