You're driving down the highway late one night at 18 m/s&nbsp;m/s&nbsp;when a deer steps onto the road 40 m&nbsp;m&nbsp;in front of you. Your reaction time before stepping on the brakes is 0.50 s&nbsp;s&nbsp;, and the maximum deceleration of your car is 12 m/s2&nbsp;m/s2&nbsp;.

Question

You&#039;re driving down the highway late one night at 18 m/s&amp;nbsp;m/s&amp;nbsp;when a deer steps onto the road 40 m&amp;nbsp;m&amp;nbsp;in front of you. Your reaction time before stepping on the brakes is 0.50 s&amp;nbsp;s&amp;nbsp;, and the maximum deceleration of your car is 12 m/s2&amp;nbsp;m/s2&amp;nbsp;.

user_27qwe · Accepted Answer

To solve this problem, we will consider the motion of the car and calculate the distance required to stop after the deer appears on the road.Given information:- Initial velocity of the car (v0) = 18 m/s- Distance to the deer (d) = 40 m- Reaction time (treaction) = 0.50 s- Maximum deceleration of the car (a) = 12 m/s2Let&#039;s proceed step by step:1. Calculate the distance traveled during the reaction time:The distance traveled by the car during the reaction time can be calculated using the formula:dreaction=v0·treaction2. Calculate the remaining distance to be covered after the reaction time:The remaining distance to be covered after the reaction time is the initial distance to the deer minus the distance traveled during the reaction time:dremaining=d−dreaction3. Calculate the stopping distance:The stopping distance is the distance required to bring the car to a complete stop. It can be calculated using the formula:dstopping=v022a4. Determine if the car can stop in time:If the stopping distance is greater than or equal to the remaining distance, the car can stop in time. Otherwise, it will collide with the deer.

You're driving down the highway late one night

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