A ball is thrown vertically upward from the ground. Its distance in feet from the ground in t seconds is s equals negative 16 t squared plus 176 t.s=−16t2+176t. After how many seconds will the ball be 448 feet from the​ ground?

Mollie Wise

Mollie Wise

Answered question

2022-11-24

A ball is thrown vertically upward from the ground. Its distance in feet from the ground in t seconds is s equals negative 16 t squared plus 176 t s = 16 t 2 + 176 t After how many seconds will the ball be 448 feet from the​ ground?

Answer & Explanation

crys07bhZ

crys07bhZ

Beginner2022-11-25Added 8 answers

When h = 16 t 2 + 176 t
Then, 16 t 2 + 176 t = 448 16 t 2 176 t + 448 = 0 t 2 11 t + 28 = 0 t 2 7 t 4 t + 28 = 0 t ( t 7 ) 4 ( t 7 ) = 0 ( t 4 ) ( t 7 ) = 0 t = 4  or  t = 7
First time at t=3 seconds ball will be at 448 feet.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Advanced Physics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?