An object's initial velocity is 40m/s and is accelerating. When the object's displacement is 300m, its velocity is -30m/s. What is the object's acceleration in (m/s^2)?

v 2 = u 2 + 2 a S a = v 2 − u 2 2 S v = − 30 m / s , u = 40 m / s , S = 300 m a = ( − 30 ) 2 − 40 2 2 × 300 a = − 1.167 m / s

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Advanced Physics

Bailee Richards

Answered question

2022-11-25

An object's initial velocity is 40m/s and is accelerating. When the object's displacement is 300m, its velocity is -30m/s. What is the object's acceleration in (m/s^2)?

Answer & Explanation

Damion Ray

Beginner2022-11-26Added 9 answers

v^{2} = u^{2} + 2 a S a = \frac{v^{2} - u^{2}}{2 S} v = - 30 m / s, u = 40 m / s, S = 300 m a = \frac{(- 30)^{2} - 40^{2}}{2 \times 300} a = - 1.167 m / s

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