A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235m below. If the plane is traveling horizontally with a speed of 250 km/h (69.4m/s), (a) how far in advance of the recipients ( horizontal distance) must the goods be dropped. (b) Suppose, instead that the plane release the supplies a horizontal distance of 425m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climber's position? (c) with what speed do the supplies land in the latter case

Question

A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235m below. If the plane is traveling horizontally with a speed of 250 km/h (69.4m/s), (a) how far in advance of the recipients ( horizontal distance) must the goods be dropped. (b) Suppose, instead that the plane release the supplies a horizontal distance of 425m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climber&#039;s position? (c) with what speed do the supplies land in the latter case

Reynaldo Hampton · Accepted Answer

a.   235  =      1    2    g      t    2   , initial velocity downwards is zero.  t  =  6.92  sHorizontal displacement of food during this period  =  6.92  ×  69.4  m  =  480.25  mb. time required to cover horizontal distance of 425 m  =      425    69.4    =  6.124  s    h  =  u  t  +      1    2    g      t    2      235  =  u  ×  6.124  +  .5  ×  9.8  ×  6.124      ²      235  =  u  ×  6.124  +  183.76    u  =  8.36  m      /    sc.   v  =  u  +  g  t  =  8.36  +  9.8  ×  6.124  =  68.37  m      /    shorizontal velocity = 69.4 m /sresultant velocity   =            68.37      2        +          69.4      2        =      4674.45    +    4816.36    =  97.42  m      /    s

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