The position of a particle as a function of time 𝑑, is given by x(t)=at+bt^2βˆ’ct^3, where a, b and c are constants. When the particle attains zero acceleration, then its velocity will be a+b^2/c a+b^2/4c a+b^2/3c a+b^2/2c

Davion Griffith

Davion Griffith

Answered question

2022-11-28

The position of a particle as a function of time 𝑑, is given by x ( t ) = a t + b t 2 βˆ’ c t 3 , where a, b and c are constants. When the particle attains zero acceleration, then its velocity will be
a+b^2/c
a+b^2/4c
a+b^2/3c
a+b^2/2c

Answer & Explanation

Lilia Nolan

Lilia Nolan

Beginner2022-11-29Added 7 answers

v = d x d t , Β  a = d v d t x ( t ) = a t + b t 2 βˆ’ c t 3 v = d x d t = a + 2 b t βˆ’ 3 c t 2 a = d v d t = 2 b βˆ’ 6 c t ∴ 2 b βˆ’ 6 c t = 0 β‡’ t = b 3 c v = a + 2 b ( b 3 c ) βˆ’ 3 c ( b 3 c ) 2 v = a + b 2 3 c

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