A 0.50-mm-diameter hole is illuminated by light of wavelength 500 nm. What is the width of the central maximum on a screen 2.0 m behind the slit?

arteriolangp

arteriolangp

Answered question

2022-12-19

A 0.50-mm-diameter hole is illuminated by light of wavelength 500 nm. What is the width of the central maximum on a screen 2.0 m behind the slit?

Answer & Explanation

Smeawnswelapno

Smeawnswelapno

Beginner2022-12-20Added 4 answers

given information
Diameter D = 0.50 m m
Wavelength λ = 500 n m
Length L = 2.0 m
To find
Width w
A bright central maximum of diameter will be present in a circular aperture of diameter D:
w = 2.44 λ L D w = ( 2.44 ( 500 10 9 m ) ( 2.0 m ) 0.50 10 3 m ) w = 4.88 10 3 m w = 4.88 m m

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